Proj Motion EX 12
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Helena Dedic
A ball is thrown from ground level. Three seconds later it is moving horizontally at 15 m/s. Find the horizontal range and the angle of impact.
Solution:
At t = 2 s, the velocity of a projectile is v = (15 m/s, 0 m/s). What is the range of the flight and the angle of impact?
Since , the projectile must be at the top of its motion at t = 2 s. The total time of the motion is then 4 s and the range is given by equation 1:
Find the velocity in the y-direction at impact taking the initial velocity as zero at the top and finding the velocity 2 s later:
The velocity at impact is v = (15 m/s, -19.6 m/s) so that the angle of impact is below the horizontal or .