Newtons Laws EX 28

The forces exerted on the child are $F_{G}$ pointing down and the normal force $F_{N}$ pointing vertically upward. The apparent weight of the child is the normal force exerted by the basket on the child.

$F_{G}-F_{N}=ma$

$F_{N}=m(g-a)$

$F_{N}=40(10-1)=360N$

The apparent weight of the child is 360 N, which is less than the actual weight.