Newtons Laws EX 28

The forces exerted on the child are $F_G$ pointing down and the normal force $F_N$ pointing vertically upward. The apparent weight of the child is the normal force exerted by the basket on the child.

$F_G-F_N=ma$

$F_N=m(g-a)$

$F_N=40(10-1)=360N$

The apparent weight of the child is 360 N, which is less than the actual weight.